4x(x-3)+2x-x^2=3x^2+40

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Solution for 4x(x-3)+2x-x^2=3x^2+40 equation: 


Simplifying
4x(x + -3) + 2x + -1x2 = 3x2 + 40

Reorder the terms:
4x(-3 + x) + 2x + -1x2 = 3x2 + 40
(-3 * 4x + x * 4x) + 2x + -1x2 = 3x2 + 40
(-12x + 4x2) + 2x + -1x2 = 3x2 + 40

Reorder the terms:
-12x + 2x + 4x2 + -1x2 = 3x2 + 40

Combine like terms: -12x + 2x = -10x
-10x + 4x2 + -1x2 = 3x2 + 40

Combine like terms: 4x2 + -1x2 = 3x2
-10x + 3x2 = 3x2 + 40

Reorder the terms:
-10x + 3x2 = 40 + 3x2

Add '-3x2' to each side of the equation.
-10x + 3x2 + -3x2 = 40 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
-10x + 0 = 40 + 3x2 + -3x2
-10x = 40 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
-10x = 40 + 0
-10x = 40

Solving
-10x = 40

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-10'.
x = -4

Simplifying
x = -4

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